C++

# Learn to check odd-even number in C++ In this article, you’ll learn how to check odd-even number in C++ programming without giving input from the keyboard or giving input from the keyboard.

Look at in the above diagram:

#### To check odd-even number we generally use modulo operator, we divide the given number with modulo operator and if get remainder == 0 then we say that the given number is even, otherwise, we say that the given number is odd.

Example 1: write a program in C++ language to check a number is odd- even without giving input from keyboard

 #include using namespace std; int main() { int num=52 ; if(num%2==0) cout<

 The Output of this program: 52 is an Even number

Example 2: write a program in C++ language to check a number is odd-even, an input is given by user from the keyboard.

Solution:

 #include using namespace std; int main() { int num ; cout<<“Enter an integer number: “; cin>>num; if(num%2==0) cout<

 The Output of this program: Enter an integer number: 36 36 is an Even number

Example 3: Write a C++ Program to check odd-even number using the ternary operator, without input from the keyboard.

Solution:

 #include using namespace std; int main() { int num=78; (num%2==0) ? cout<

 The output of this program: 78 is an Even number

Note: Ternary operator must write in a single statement;

The syntax of the ternary operator or conditional operator:

 (condition) ? statement 1: statement 2;

Note: if the condition is true then statement 1 is executed and if the condition is false statement 2 is executed.

Example 4: Write a C++ Program to check odd-even number using ternary operator, with input from the keyboard

Solution:

 #include using namespace std; int main() { int num; cout<<“Enter an integer number: “; cin>>num; (num%2==0) ? cout<

 The output of this program: Enter an integer number: 57 57 is an Odd number

Example 4: Write a C++ Program to check odd-even number without using module (%) operator, without input from the keyboard.

 #include using namespace std; int main() { int num=69 ; if(num &1) cout<

 The output of this program: 69 is an Odd number

Note: In the above program we use & (bitwise AND) operator, this operator works on the binary number. When we transform an even number into binary form then its last bit always 0 and binary of number 1 in the last bit is 1 then we get result 0 (false). since 0*1=0 it means else part is executed, on the other hand, if we transform an odd number into binary form then its last digit always 1 and it gives true and if part is executed.

Example 5: Write a C++ Program to check odd-even number without using module (%) operator, with input from the keyboard.

 #include #include int main() { int num; printf(“Enter a integer number: “); scanf(“%d”,&num); if (num & 1) printf(“%d is an Odd number “,num); else printf(“%d is an Even number”,num); getch(); }

 The Output of this program: Enter an integer number: 96 96 is an Even number